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Survey University of Phoenix Material Statistics

Question 1

This is a frequency distribution. A frequency distribution summarizes groupings of data into mutually exclusive classes and the number of occurrences in a class. In this example, the groupings are Poplar weights in Kg. for year 2, and the number of occurrences is the frequency.

Question 2

Don't waste your time!

This is a histogram. A histogram is usually a representation of tabulated frequencies, which are shown as contiguous rectangles, erected over distinct intervals, and their area equivalent to the frequency of the observations in the intervals. In this example, the frequency is on the left-hand side, and the area of the rectangle is equal to the frequency of the observations.

Question 3

This is a scatter plot. In a scatter plot, the data is presented as a collection of points. In this example, the dots represent the points that correspond to a value in the horizontal and vertical axis.

Question 4

Mean is calculated as image3.png

= 385/12

= 32.08

This means implies that, on average, it took 29.5 minutes for the premedical students to exercise.

Question 5

Median involves arranging the observations in ascending order.

If n is odd, Median(M) = value of ((n+1)/2)th item term.

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If n is even then median(M) = value of {((n)/2)th +[((n)/2)+1]th}/2

In our case, we have an even number;

Ans=32.5.

The median implies that the middle observation is 32.5

Question 6

Mode is the observation that appears most.

In this case, it is 31. This is the number of minutes that was observed by more students in exercise capacity.

Question 7

The standard deviation for a discrete random variable is calculated as; image4.png

Ans= 7.50101

Question 8

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The z score is calculated as

Ans = 1.18917319

Question 9

Ans = 1.07692308

Alisha's grandmother has a relatively longer exercise capacity compared to her peers.

Question 10

The likelihood of each team winning is 0.25. This suggests that each of the four teams has the same probability of winning. It is the estimation of how likely that something will happen.

Question 11

The probability of a randomly selected cell phone user developing cancer is 0.000003213. The result is different from the probability of 0.000340 for the general population. This result suggests that it is not true that cell phones cause cancer.

Question 12

The probability of selecting a red butterfly or one collected in spring is;

68/185+54/185

=0.6595

Question 13

4/185? 43/185?7/185

Ans = 0.00019

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The multiplication rule is when one wants to calculate the probability of one variable and the other.

Question 17

This procedure results in a binomial distribution. This is because there are two variables involved in the distribution.

Question 15

This procedure does not result in a binomial distribution because three variables are involved.

Question 16

Asking the patients as they get into the office whether they were flossed before they were appointed.

Question 17

Researching the northern spotted owl's number of feedings per month.

Question 18

Surveying 2,080 North Americans in order to determine the number of fire ant bites they suffered in the past one year.

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